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PostgreSQL7.0手册-程序员手册 -48. 服务器编程接口

减小字体 增大字体 作者:不详  来源:supcode.com收集整理  发布时间:2005-7-23 12:21:59
            for (ret = 0; ret < proc; ret++)
                {
                        HeapTuple tuple = tuptable->vals[ret];
                        
                        for (i = 1, buf[0] = 0; i <= tupdesc->natts; i++)
                                sprintf(buf + strlen (buf), " %s%s",
                                        SPI_getvalue(tuple, tupdesc, i),
                                        (i == tupdesc->natts) ? " " : " |");
                        elog (NOTICE, "EXECQ: %s", buf);
                }
        }

        SPI_finish();

        return (proc);
}
然后,编译并创建函数: 
create function execq (text, int4) returns int4 as '...path_to_so' language 'c';
vac=> select execq('create table a (x int4)', 0);
execq
-----
    0
(1 row)

vac=> insert into a values (execq('insert into a values (0)',0));
INSERT 167631 1
vac=> select execq('select * from a',0);
NOTICE:EXECQ:  0 <<< inserted by execq

NOTICE:EXECQ:  1 <<< value returned by execq and inserted by upper INSERT

execq
-----
    2
(1 row)

vac=> select execq('insert into a select x + 2 from a',1);
execq
-----
    1
(1 row)

vac=> select execq('select * from a', 10);
NOTICE:EXECQ:  0 

NOTICE:EXECQ:  1 

NOTICE:EXECQ:  2 <<< 0 + 2, only one tuple inserted - as specified

execq
-----
    3            <<< 10 is max value only, 3 is real # of tuples
(1 row)

vac=> delete from a;
DELETE 3
vac=> insert into a values (execq('select * from a', 0) + 1);
INSERT 167712 1
vac=> select * from a;
x
-
1                <<< no tuples in a (0) + 1
(1 row)

vac=> insert into a values (execq('select * from a', 0) + 1);
NOTICE:EXECQ:  0 
INSERT 167713 1
vac=> select * from a;
x
-
1
2                <<< there was single tuple in a + 1
(2 rows)

--   This demonstrates data changes visibility rule:

vac=> insert into a select execq('select * from a', 0) * x from a;
NOTICE:EXECQ:  1 
NOTICE:EXECQ:  2 
NOTICE:EXECQ:  1 
NOTICE:EXECQ:  2 
NOTICE:EXECQ:  2 
INSERT 0 2
vac=> select * from a;
x
-
1
2
2                <<< 2 tuples * 1 (x in first tuple)
6                <<< 3 tuples (2 + 1 just inserted) * 2 (x in second tuple)
(4 rows)             ^^^^^^^^ 
                     tuples visible to execq() in different invocations

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