PostgreSQL7.0手册-程序员手册 -48. 服务器编程接口
for (ret = 0; ret < proc; ret++)
{
HeapTuple tuple = tuptable->vals[ret];
for (i = 1, buf[0] = 0; i <= tupdesc->natts; i++)
sprintf(buf + strlen (buf), " %s%s",
SPI_getvalue(tuple, tupdesc, i),
(i == tupdesc->natts) ? " " : " |");
elog (NOTICE, "EXECQ: %s", buf);
}
}
SPI_finish();
return (proc);
}
然后,编译并创建函数:
create function execq (text, int4) returns int4 as '...path_to_so' language 'c';
vac=> select execq('create table a (x int4)', 0);
execq
-----
0
(1 row)
vac=> insert into a values (execq('insert into a values (0)',0));
INSERT 167631 1
vac=> select execq('select * from a',0);
NOTICE:EXECQ: 0 <<< inserted by execq
NOTICE:EXECQ: 1 <<< value returned by execq and inserted by upper INSERT
execq
-----
2
(1 row)
vac=> select execq('insert into a select x + 2 from a',1);
execq
-----
1
(1 row)
vac=> select execq('select * from a', 10);
NOTICE:EXECQ: 0
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2 <<< 0 + 2, only one tuple inserted - as specified
execq
-----
3 <<< 10 is max value only, 3 is real # of tuples
(1 row)
vac=> delete from a;
DELETE 3
vac=> insert into a values (execq('select * from a', 0) + 1);
INSERT 167712 1
vac=> select * from a;
x
-
1 <<< no tuples in a (0) + 1
(1 row)
vac=> insert into a values (execq('select * from a', 0) + 1);
NOTICE:EXECQ: 0
INSERT 167713 1
vac=> select * from a;
x
-
1
2 <<< there was single tuple in a + 1
(2 rows)
-- This demonstrates data changes visibility rule:
vac=> insert into a select execq('select * from a', 0) * x from a;
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2
NOTICE:EXECQ: 2
INSERT 0 2
vac=> select * from a;
x
-
1
2
2 <<< 2 tuples * 1 (x in first tuple)
6 <<< 3 tuples (2 + 1 just inserted) * 2 (x in second tuple)
(4 rows) ^^^^^^^^
tuples visible to execq() in different invocations
--------------------------------------------------------------------------------
{
HeapTuple tuple = tuptable->vals[ret];
for (i = 1, buf[0] = 0; i <= tupdesc->natts; i++)
sprintf(buf + strlen (buf), " %s%s",
SPI_getvalue(tuple, tupdesc, i),
(i == tupdesc->natts) ? " " : " |");
elog (NOTICE, "EXECQ: %s", buf);
}
}
SPI_finish();
return (proc);
}
然后,编译并创建函数:
create function execq (text, int4) returns int4 as '...path_to_so' language 'c';
vac=> select execq('create table a (x int4)', 0);
execq
-----
0
(1 row)
vac=> insert into a values (execq('insert into a values (0)',0));
INSERT 167631 1
vac=> select execq('select * from a',0);
NOTICE:EXECQ: 0 <<< inserted by execq
NOTICE:EXECQ: 1 <<< value returned by execq and inserted by upper INSERT
execq
-----
2
(1 row)
vac=> select execq('insert into a select x + 2 from a',1);
execq
-----
1
(1 row)
vac=> select execq('select * from a', 10);
NOTICE:EXECQ: 0
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2 <<< 0 + 2, only one tuple inserted - as specified
execq
-----
3 <<< 10 is max value only, 3 is real # of tuples
(1 row)
vac=> delete from a;
DELETE 3
vac=> insert into a values (execq('select * from a', 0) + 1);
INSERT 167712 1
vac=> select * from a;
x
-
1 <<< no tuples in a (0) + 1
(1 row)
vac=> insert into a values (execq('select * from a', 0) + 1);
NOTICE:EXECQ: 0
INSERT 167713 1
vac=> select * from a;
x
-
1
2 <<< there was single tuple in a + 1
(2 rows)
-- This demonstrates data changes visibility rule:
vac=> insert into a select execq('select * from a', 0) * x from a;
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2
NOTICE:EXECQ: 1
NOTICE:EXECQ: 2
NOTICE:EXECQ: 2
INSERT 0 2
vac=> select * from a;
x
-
1
2
2 <<< 2 tuples * 1 (x in first tuple)
6 <<< 3 tuples (2 + 1 just inserted) * 2 (x in second tuple)
(4 rows) ^^^^^^^^
tuples visible to execq() in different invocations
--------------------------------------------------------------------------------

